![]() do take this with a pinch of salt as it not a very reliable method it depends on how good your multimeter is. The pin with higher voltage drop will be your emitter and the other will be your collector. For this place your positive lead on base pin and check for voltage dorp on diode mode for the other pins. A transistor has three zones emitter, base and collector, and can be built two different ways, as NPN or PNP. The emitter is always forward biased in relation to the base in order to supply the base with the bulk of charge carriers. The function of an emitter is to supply majority charge carriers to the base. Now we have to find the emitter and collector pin. Emitter The first section is called the emitter. Since the combination is NPN transistor that is it has a diode in either direction. Put you meter in diode mode and try the pin combinations for pins 1+2, 1+3, and 2+3 since the transistor is a NPN transistor at one pin for both forward and reverse ou will get a voltage drop of 0.5 to 0.7 V. ![]() Its just the inverse for PNP.Īlas! if you transistor is not metal cased you have to go through a tiring process. Now put the meter in diode mode and check the other two pins, if the positive lead is placed on the base and the negative on emitter then you meter will read a voltage drop of 0.5 to 0.7 for a NPN transistor. Simply put your multi-meter in continuity mode and check which pin is in connecting with the metal casing. It has an emitter, base, and collector which correspond to the cathode, grid, and plate, respectively, in the triode tube. If you transistor is metal cased, then you work is reduce by more than half. It seems over the wide range of base current. Ive seen one figure (see attached image). The best and quickest way to find the pinout of any component is to do a quick google search or by checking its dasheet.īut lets assume you are left only with a multimeter and a transistor and have no signal for internet this technique can help youįinding pinout for metal casing transistor: It appears that base-emitter voltage (Vbe) in transistor is always assumed as 0.6 V in circuit analysis. Again resistor is added from base to guessed collector. Now swap guessed emitter and collector and repeat. ![]() Connect base to guessed collector via a high value resistor - probably 100k to 1M. Hi Abhimanyu, welcome to circuit digest forums. Connect positive to guessed collector for NPN and negative to guessed emitter.
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